tangent of f(x)=4x^2-4x+1, x=1

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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log_□

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
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tangent of f(x)=4x²−4x+1, x=1

Solution

y=4x−3

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Solution steps

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Find the tangent point: (1, 1)

Find the slope of f(x)=4x²−4x+1: 8x−4

Compute the slope at x=1: m=4

Find the line with slope m=4 and passing through (1, 1): y=4x−3

y=4x−3

Tangent Line Examples

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

tangent of f(x)=4x^2-4x+1, x=1

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